
By NeurofiED Editorial Team · Reviewed by NeurofiED Learning Science Team
NeurofiED resources are written for UK 11+ families and reviewed against the platform's retrieval practice, spacing, interleaving and feedback principles.
Help a Year 5 child represent multi-step word problems, choose operations, label intermediate results and check answers with clear worked examples.
For multi-step word problems, do not begin by calculating. First decide what the final answer must describe, represent how the quantities are connected, and write a short operation plan. Then solve one labelled step at a time, carry each intermediate result forward, and check the finished answer against the story.
The difficult part is often not the arithmetic. It is deciding whether a quantity should be combined, compared, repeated, shared or removed. England’s mathematics curriculum makes that decision part of problem solving: its aims include solving routine and non-routine problems by breaking them into simpler steps.[2] The goal is not to hunt for a keyword, but to explain why each operation fits.
A multi-step problem needs two or more connected calculations before the question can be answered. The result of one calculation becomes useful information for the next. For example, you might find the total number of seats before subtracting empty seats, or find the amount raised before comparing it with a target.
Three habits matter: represent the relationships, label intermediate results and keep the final question in view. Write “total seats = 192”, not an unexplained “192”.
The focus is the whole problem chain and the choice of operations, rather than one written or mental calculation method. Reading the situation matters, but the mathematical work is to connect its quantities.
The curriculum develops this reasoning over time. Year 4 pupils solve addition and subtraction two-step problems in context, “deciding which operations and methods to use and why”. Year 6 pupils meet addition and subtraction multi-step problems with the same emphasis on choice and justification, alongside estimation to check answers.[2] These are useful reference points; individual 11+ papers may use different formats.
Read the final sentence first, then the whole problem. Ask what the answer must describe, which unit it needs and whether it is likely to be a total, difference, number of groups, amount per group or remainder. Write an answer stem such as “There are ___ pupils in the hall.”
Record each number with its role, not by itself. If the problem says there are eight rows with 24 seats in each, draw eight equal boxes or write `8 groups × 24 seats`. If 37 seats are empty, show that they are removed from the total capacity.
A representation earns its place only when it clarifies the mathematics. The Education Endowment Foundation recommends using representations with a clear purpose, to reveal mathematical structure and support pupils towards using mathematics independently.[3] That supports purposeful diagrams; it does not mean that this exact home routine has been tested as an intervention.
Write a short chain in words:
> total capacity = rows × seats per row > occupied seats = total capacity − empty seats
The plan can contain blanks. Its job is to settle the relationships before arithmetic competes for attention.
Complete one line at a time. Keep units and labels beside intermediate answers. If the second calculation uses the first result, make that link visible rather than squeezing everything into one unexplained expression.
Check that each operation matches the story, that the answer has a sensible size, and that estimation or a reverse operation supports the arithmetic.
A hall has 8 rows of 24 seats. For a performance, 37 seats are empty. How many seats are occupied?
Eight equal rows indicate repeated equal groups, so multiplication finds the hall’s total capacity. Empty seats are part of that capacity but are not occupied, so subtract them.
> total seats = 8 × 24 > occupied seats = total seats − 37
> 8 × 24 = 192 seats in total > 192 − 37 = 155 occupied seats
The answer is 155 occupied seats.
Round 37 to 40: `192 − 40 = 152`, so 155 is sensible. Reverse the subtraction: `155 + 37 = 192`. The intermediate answer, 192, is necessary but is not the requested answer because it includes empty seats.
A community group wants to raise £500. It collects £186 on Saturday and £149 on Sunday, then pays £58 for materials. How much more money does it need after costs?
The two collections combine. The materials cost comes out of that amount. The final question asks for the gap between the net amount and the £500 target.
> collected = Saturday + Sunday > net amount = collected − materials > still needed = target − net amount
> £186 + £149 = £335 collected > £335 − £58 = £277 after costs > £500 − £277 = £223 still needed
The group needs £223 more.
The net amount must be less than £335 because a cost was paid. The remaining gap must be less than £500 because some money has been raised. Finally, `£277 + £223 = £500` confirms the comparison.
“More” is not an instruction to add. Here, “how much more is needed?” asks for the difference from the target, so subtraction fits.
A school shares 288 pencils equally among 9 classes. Each class keeps 7 pencils as spares and puts the rest into desk trays. How many pencils go into desk trays altogether?
Equal sharing means divide to find one class’s share. Then remove seven spares from each class’s share. Finally, multiply the tray amount per class by nine classes.
> pencils per class = 288 ÷ 9 > tray pencils per class = share − 7 > tray pencils altogether = tray amount × 9
> 288 ÷ 9 = 32 pencils per class > 32 − 7 = 25 tray pencils per class > 25 × 9 = 225 tray pencils altogether
The answer is 225 pencils in desk trays.
There are `7 × 9 = 63` spare pencils altogether. Subtracting all spares from the original total gives `288 − 63 = 225`. Two different valid routes reach the same answer.
The order matters. Subtracting seven before sharing would keep only seven spares across the whole school, not seven per class.
A library has 1,248 children’s books. It receives 376 new books and removes 189 damaged books. How many children’s books does it have now?
New books increase the total; damaged books being removed decrease it.
> 1,248 + 376 = 1,624 > 1,624 − 189 = 1,435
The library now has 1,435 children’s books.
Round to nearby hundreds: `1,200 + 400 − 200 = 1,400`. The exact answer, 1,435, is close enough to be plausible. A useful combined check is to find the net change: `376 − 189 = 187`, then `1,248 + 187 = 1,435`.
This example shows why labelled steps matter. The number 1,624 is the total before damaged books are removed, not the final stock.
Context, not one word, decides the operation. Ask what is happening to the quantities.
| Relationship | Useful question | Likely operation | |---|---|---| | Combine parts | What is the total? | addition | | Remove or find a gap | What remains or what is the difference? | subtraction | | Repeat equal groups | How many altogether in equal groups? | multiplication | | Share or group equally | How many in each group, or how many groups? | division |
Do not turn the table into a keyword list. “Each” can signal multiplication for equal groups or division for equal sharing. Represent the relationship before choosing the symbol.
If two operations seem possible, say what each would mean. For the hall example, `8 + 24` combines a count of rows with seats per row, quantities that should not be added. `8 × 24` represents eight equal groups of 24 seats.
If support is needed, provide part of the representation or plan while leaving the arithmetic to the child. Remove prompts as the child becomes ready to choose independently.
Pause before arithmetic. Ask the child to explain what a proposed calculation would find. If `500 + 58` has no useful meaning in the fundraiser story, it does not belong in the plan.
Replace “Which word tells you the operation?” with “What is the relationship?” Ask whether quantities are being combined, removed, repeated, shared or compared.
Give every line a label and carry that label into the next step. A small table with columns for calculation, result and meaning can help.
Read the answer stem again. In the pencil problem, 32 answers “How many pencils per class?”, not “How many go into trays altogether?”
Reduce the load without removing the reasoning: use smaller numbers, read one sentence at a time, supply a clean diagram, or offer two possible first operations and discuss what each would find.
Ask for a second route, add unnecessary information, or ask your child to write a matching problem for a given operation chain.
Underline the final question and important quantities, but do not let a single word choose the operation. Label what each quantity represents and describe its relationship to the others.
No. A bar model is useful for part–whole and comparison relationships; equal-group boxes, tables or labelled lists may be clearer elsewhere. Use the simplest representation that exposes the structure.
Not initially. Separate labelled lines make the meaning and intermediate results easier to inspect. A compact expression can be written afterwards if it remains unambiguous.
Return to the operation plan. Ask what each calculation actually found, whether the final question was answered and whether the unit fits. Recalculate only after checking the representation.
Estimate the expected size, reverse an operation, or take a second route. Independent checks are stronger than copying the same calculation again.
Choose one worked example above. Cover its solution and ask your child to produce only three things first: an answer stem, a labelled representation and a word plan. Once those agree with the story, calculate and check each step.
[2] https://www.gov.uk/government/publications/national-curriculum-in-england-mathematics-programmes-of-study — Department for Education, National curriculum in England: mathematics programmes of study.
[3] https://educationendowmentfoundation.org.uk/education-evidence/guidance-reports/maths-ks-2-3 — Education Endowment Foundation, Improving Mathematics in Key Stages 2 and 3.
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